document.write( "Question 737616: Give a counterexample to show that (x+y)2 = x2 + y2 is false. \n" ); document.write( "
Algebra.Com's Answer #450457 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
\r
\n" ); document.write( "\n" ); document.write( "To find a counter example to \"\"%28x%2B+y%29%5E2\" is \"NOT\" \"x%5E2%2B+y%5E2\"\", you must use \"x\" and \"y\" so that \"%28x%2By%29%5E2=+x%5E2%2B+y%5E2\".\r
\n" ); document.write( "\n" ); document.write( "Presumably you know that \"%28x%2B+y%29%5E2=+x%5E2%2B+2xy%2B+y%5E2\". That means you must find \"x\" and \"y\" so that \"x%5E2%2B+2xy%2B+y%5E2=+x%5E2%2B+y%5E2\".\r
\n" ); document.write( "\n" ); document.write( "\"cross%28x%5E2%29%2B+2xy%2B+cross%28y%5E2%29=+cross%28x%5E2%29%2B+cross%28y%5E2%29\"...notice that the squares on both sides cancel\r
\n" ); document.write( "\n" ); document.write( " What does that leave you with? \r
\n" ); document.write( "\n" ); document.write( "\"2xy=+0\"...this is true only if only \"x=0\" or \"y=0\", or both \"x=0\" and \"y=0\"\r
\n" ); document.write( "\n" ); document.write( "so, it proves that \"%28x%2B+y%29%5E2%3C%3Ex%5E2%2B+y%5E2\"\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );