document.write( "Question 737355: The product of three consecutive odd integers is reduced by 23. That result is 99 less than the cube of the sum of the number 2 and the smallest of the three consecutive odd integers.\r
\n" ); document.write( "\n" ); document.write( "Determining the mean of the three consecutive odd integers is your task. \n" ); document.write( "

Algebra.Com's Answer #450379 by sachi(548) $\"\"$ $\"About$

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let the three consecutive odd integers are a-2,a,a+2
\n" ); document.write( "The product of three consecutive odd integers is reduced by 23. That result is 99 less than the cube of the sum of the number 2 and the smallest of the three consecutive odd integers.
\n" ); document.write( "so (a-2)a(a+2)-23=-99+[2+(a-2)]^3=-99+a^3
\n" ); document.write( "or a^3-4a-a^3=-99+23=-76
\n" ); document.write( "or -4a=-76
\n" ); document.write( "or a=19
\n" ); document.write( "so the nos are 17,19,21
\n" ); document.write( "the mean of the three consecutive odd integers =(17+19+21)/3=19 \n" ); document.write( "

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