document.write( "Question 737409: Dear tutor,
\n" ); document.write( "For the problem: Write an equation of the line that passes through the given point and is parallel to the given line (18,2), 3y=x-12
\n" ); document.write( "I went through these steps:
\n" ); document.write( "changed the equation to slope-intercept form: y=1/3x-4
\n" ); document.write( "Then plugged in the x and y variables from the point and the slope and solved for b:
\n" ); document.write( "y=mx+b
\n" ); document.write( "2=1/3(18)+b
\n" ); document.write( "b=-4
\n" ); document.write( "And ended up getting the equation y=1/3x-4, which is the same as the original! Is this correct or did I do something wrong? Thanks for the help!
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Algebra.Com's Answer #450362 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
It looks like the point ( 18,2 ) is
\n" ); document.write( "on the given line
\n" ); document.write( "\"+3y+=+x+-+12+\"
\n" ); document.write( "\"+3%2A2+=+18+-+12+\"
\n" ); document.write( "\"+6+=+6+\"
\n" ); document.write( "-----------
\n" ); document.write( "The line is parallel to itself, so the
\n" ); document.write( "answer is OK
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