document.write( "Question 737416: A man is 32 years older than his son,ten years ago he was 3 times as old as his son.find the present age of each. \n" ); document.write( "

Algebra.Com's Answer #450360 by Susan-math(40) $\"\"$ $\"About$

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Let m=man's age
\n" ); document.write( "Then s =son's age = m-32\r
\n" ); document.write( "\n" ); document.write( "Man's age ten years ago was m-10
\n" ); document.write( "Son's age ten years ago was m - 32 -10=m-42
\n" ); document.write( "But we also know man 10 years ago = 3* son 10 years ago \r
\n" ); document.write( "\n" ); document.write( "So $\"m-10=3%2A%28m-42%29\"$
\n" ); document.write( "Distribute and simplify:
\n" ); document.write( "M
\n" ); document.write( " $\"m-10=3m-3%2842%29=3m-126\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"m-10=3m-126\"$
\n" ); document.write( "Subtract m from both sides
\n" ); document.write( " $\"-10=2m-126\"$
\n" ); document.write( "Add 126 to both sides
\n" ); document.write( " $\"116=2m\"$ and divide by 2 on both sides to get m =58.\r
\n" ); document.write( "\n" ); document.write( "So the man is now 58 years old. Going to the top, we find his son is 32 years younger, so his son is 58-32=26.\r
\n" ); document.write( "\n" ); document.write( "To check, go back ten years: the man was 48 and his son was 16 and 48=3*16.\r
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