document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=64414>Question 64414</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve.     x^2 + 5x + 6 = 0 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #45036 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=45036\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> To solve:  x^2+5x+6=0\r<BR>\n" );
document.write( "\n" );
document.write( "The factors of 6 are: (3)(2) and (6)(1)\r<BR>\n" );
document.write( "\n" );
document.write( "In the general form of the quadratic equation (Ax^2+Bx+C=0), if A=1, then B=the sum of the factors of C. Thus, in our equation, the factors of C that add up to 5 are (3)(2) which gives us:\r<BR>\n" );
document.write( "\n" );
document.write( "(x+3)(x+2)=0<BR>\n" );
document.write( "x+3=0<BR>\n" );
document.write( "x=-3 and<BR>\n" );
document.write( "x+2=0<BR>\n" );
document.write( "x=-2\r<BR>\n" );
document.write( "\n" );
document.write( "We can also rewrite our equation:<BR>\n" );
document.write( "x^2+5x+6=0 rewrite as:<BR>\n" );
document.write( "x^2+3x+2x+6=0 which equals<BR>\n" );
document.write( "x(x+3)+2(x+3)=0<BR>\n" );
document.write( "(x+3)(x+2)=0 and we arrive at the same solution.\r<BR>\n" );
document.write( "\n" );
document.write( "Hope this helps.  Happy holidays----ptaylor\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );