document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=737391>Question 737391</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What must be the rate in miles per hour of a truck if it wants to make a 20 mile trip in 40 minutes </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #450352 by </B><A HREF=/tutors/aboutme.mpl?userid=Susan-math><B>Susan-math(40)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Susan-math><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=450352\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Distance = (rate)*(time) so we write d=rt\r<BR>\n" );
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document.write( "D=20 miles<BR>\n" );
document.write( "R=?<BR>\n" );
document.write( "T=40 minutes=40/60 hours=2/3\r<BR>\n" );
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document.write( "So 20=r (2/3)\r<BR>\n" );
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document.write( "Multiply both sides by the reciprocal of 2/3, (which is 3/2) to get r alone.<BR>\n" );
document.write( "So r = 20(3/2)=60/2=30 mph\r<BR>\n" );
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document.write( "Check: rate*time= (30)(2/3)=20 miles </SPAN>\n" );
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