document.write( "Question 737371: Please help me solve
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document.write( "(4x)^2 + sqrt(2x+3) = 8x + 1
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document.write( "Thanks a lot, i'm really appreciate your help! \n" );
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Algebra.Com's Answer #450330 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! (4x)^2 + sqrt(2x+3) = 8x + 1 \n" ); document.write( "---- \n" ); document.write( "sqrt(2x+3) = -4x^2+8x+1 \n" ); document.write( "--- \n" ); document.write( "2x+3 = (-4x^2+8x+1)(-4x^2+8x+1) \n" ); document.write( "----- \n" ); document.write( "2x + 3 = 16x^4-32x^3-4x^2 -32x^3+64x^2 + 8x - 4x^2+8x+1 \n" ); document.write( "2x+3 = 16x^4 - 64x^3 + 56x^2 + 16x + 1 \n" ); document.write( "---- \n" ); document.write( "16x^4 - 64x^3 + 56x^2 + 14x -2 = 0 \n" ); document.write( "---- \n" ); document.write( "8x^4 - 32x^3 + 28x^2 + 7x - 1 = 0 \n" ); document.write( "-------------- \n" ); document.write( "I graphed it and found zeroes at \n" ); document.write( "x = -0.28.., x = +0.104.., x = 1.78.. and x = 2.40... \n" ); document.write( "------ \n" ); document.write( "Check for extraneous zeroes. \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "================ \n" ); document.write( " |