document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=737328>Question 737328</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Mr. Tennyson divides an amount of money between his three children Abigail, Ben, and Chuck in the ratio 3:2:7.  If Chuck received $120 more than Abigail, how much did Ben receive? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #450300 by </B><A HREF=/tutors/aboutme.mpl?userid=DrBeeee><B>DrBeeee(684)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=DrBeeee><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=450300\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Four years ago, one of my math wizards came up with a straight forward, if not simple, method of solving proportional problems like yours. I call it the Nicole n, named after her.<BR>\n" );
document.write( "You are given<BR>\n" );
document.write( "(1) a:b:c = 3:2:7 and since all ratios are equivalent (equal) so is<BR>\n" );
document.write( "(2) a:b:c = 3n:2n:7n<BR>\n" );
document.write( "Now treat the numbers 3n, 2n and 7n as if they are the amount of money each recieved. Then the statement that c received 120 more than a yields the equation<BR>\n" );
document.write( "(3) 7n = 3n + 120 or<BR>\n" );
document.write( "(4) 4n = 120 or<BR>\n" );
document.write( "(5) n = 30<BR>\n" );
document.write( "Put n into (2) we get<BR>\n" );
document.write( "(6) a:b:c = 90:60:210<BR>\n" );
document.write( "Therefore Abby got $90, Ben got $60 and Chuck got $210.<BR>\n" );
document.write( "Note that Chuck got $120 more than Abby!<BR>\n" );
document.write( "Couldn't be easier, could it!!!!<BR>\n" );
document.write( "  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );