document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=737137>Question 737137</A>: <I><SPAN STYLE=\"word-break: break-all;\"> three times a number added to twice a smaller number is 4. twice the smaller number less than twice the larger number is 6. find the numbers\r<BR>\n" );
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document.write( "help :( </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #450263 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=450263\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> we are given\r<BR>\n" );
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document.write( "3i + 2j = 4\r<BR>\n" );
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document.write( "and 2j - 2i = 6\r<BR>\n" );
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document.write( "therefore 2j = 2i + 6  and\r<BR>\n" );
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document.write( "j = i + 3\r<BR>\n" );
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document.write( "substitute in the first equation\r<BR>\n" );
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document.write( "3i + 2 * (i+3) = 4\r<BR>\n" );
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document.write( "3i + 2i + 6 = 4\r<BR>\n" );
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document.write( "5i = -2\r<BR>\n" );
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document.write( "i = -2/5 and  -6/5 + 2j = 4, -6 + 10j = 20, j = 26/10 = 13/5\r<BR>\n" );
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document.write( "i = -2/5 and j=13/5 </SPAN>\n" );
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