document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=737226>Question 737226</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of two integers is 85. Ten less than three times the smaller of the integers is equal to twenty more than twice the larger integer. Find the numbers using only one unknown.\r<BR>\n" );
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document.write( "I tried doing it using two unknowns and i got 41 and 47.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #450248 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=450248\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> we know that i+j = 85 and\r<BR>\n" );
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document.write( "3i-10 = 2j+20\r<BR>\n" );
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document.write( "solve for i = 2j/3 + 10/3  \r<BR>\n" );
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document.write( "substitute in equation 1 for i\r<BR>\n" );
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document.write( "2j/3 +10/3 + j = 85\r<BR>\n" );
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document.write( "multiply both sides by 3\r<BR>\n" );
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document.write( "2j + 10 +  3j = 255\r<BR>\n" );
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document.write( "5j = 245  and j = 49 and i = 36\r<BR>\n" );
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document.write( " </SPAN>\n" );
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