document.write( "Question 737120: I need help with the following math question:\r
\n" ); document.write( "\n" ); document.write( "The maximum depth of water in a circular pipe of radius 25 cm is 18 cm. Find the width of the water surface across the pipe.
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Algebra.Com's Answer #450179 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
The distance from the center of the pipe to the surface
\n" ); document.write( "of the water in the pipe is \"+25+-+18+=+7+\" cm
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\n" ); document.write( "Also, the distance from the center of the pipe to where
\n" ); document.write( "the surface contacts the pipe is the radius, \"+25+\"
\n" ); document.write( "This forms a right triangle when you include the surface
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\n" ); document.write( "Call ( center of water surface to where surface meets pipe ) = \"+x+\"
\n" ); document.write( "Now I can say
\n" ); document.write( "\"+25%5E2+-+7%5E2+=+x%5E2+\"
\n" ); document.write( "\"+625+-+49+=+x%5E2+\"
\n" ); document.write( "\"+x%5E2+=+576+\"
\n" ); document.write( "\"+x+=+24+\"
\n" ); document.write( "The is 1/2 of the width of the water's surface, so
\n" ); document.write( " the width of the water surface across the pipe is 48 cm\r
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