document.write( "Question 736460: I have tried several different ways to write this hyperbola in standard form and cannot get it. Could I have some help? \r
\n" ); document.write( "\n" ); document.write( "Write -16x^2+4y^2-64x+24y+36=0 in standard form.
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Algebra.Com's Answer #450178 by lwsshak3(11628)\"\" \"About 
You can put this solution on YOUR website!
write this hyperbola in standard form
\n" ); document.write( "\"-16x%5E2%2B4y%5E2-64x%2B24y%2B36=0\"
\n" ); document.write( "rearrange terms
\n" ); document.write( "\"-16x%5E2-64x%2B4y%5E2%2B24y%2B36=0\"
\n" ); document.write( "complete the square
\n" ); document.write( "\"-16%28x%5E2%2B4x%2B4%29%2B4%28y%5E2%2B6y%2B9%29=-36-64%2B36\"
\n" ); document.write( "\"-16%28x%2B2%29%5E2%2B4%28y%2B3%29%5E2=-64\"
\n" ); document.write( "divide by -64
\n" ); document.write( "\"%28x%2B2%29%5E2%2F4-%28y%2B3%29%5E2%2F16=1\"
\n" ); document.write( "This is an equation of a hyperbola with horizontal transverse axis.
\n" ); document.write( "Its standard form:\"%28x-h%29%5E2%2Fa%5E2-%28y-k%29%5E2%2Fb%5E2=1\", (h,k)=(x,y) coordinates of center
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