document.write( "Question 736705: Would you please help me with a problem I don't seem to understand how to do? I need help converting this equation: \"+-9x%5E2%2B4y%5E2-54x%2B8y-113=0+\" into it's standard form. I have already figured out the general equation is a hyperbola, but can't seem to work it out.\r
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Algebra.Com's Answer #450173 by lwsshak3(11628)\"\" \"About 
You can put this solution on YOUR website!
\"-9x%5E2%2B4y%5E2-54x%2B8y-113=0+\"
\n" ); document.write( "rearrange terms
\n" ); document.write( "\"-9x%5E2-54x%2B4y%5E2%2B8y-113=0+\"
\n" ); document.write( "complete the square:
\n" ); document.write( "\"-9%28x%5E2%2B6x%2B9%29%2B4%28y%5E2%2B2y%2B1%29=113-81%2B4+\"
\n" ); document.write( "\"-9%28x%2B3%29%5E2%2B4%28y%2B1%29%5E2=36\"
\n" ); document.write( "rearrange terms:
\n" ); document.write( "\"4%28y%2B1%29%5E2-9%28x%2B3%29%5E2=36\"
\n" ); document.write( "divide by 36
\n" ); document.write( "\"%28y%2B1%29%5E2%2F9-%28x%2B3%29%5E2%2F4=1\"
\n" ); document.write( "This is an equation of a hyperbola with vertical transverse axis:
\n" ); document.write( "Its standard form: \"%28y-k%29%5E2%2Fa%5E2-%28x-h%29%5E2%2Fb%5E2=1\", (h,k)=(x,y) coordinates of center.
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