document.write( "Question 737103: If a square with a side of 5 is inscribed in a circle, what is the circumference of the circle? \n" ); document.write( "
Algebra.Com's Answer #450154 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "Since the square is inscribed in a circle, the \"vertices\" of the square touches the circle. Hence the \"diameter\" of the circle is the \"diagonal\" of the square. \r
\n" ); document.write( "\n" ); document.write( "Now, the length of the diagonal is obtained by using Pythagoras theorem, and the area and the \"diameter\" is\r
\n" ); document.write( "\n" ); document.write( "\"d%5E2=5%5E2%2B5%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"d%5E2=25%2B25\"\r
\n" ); document.write( "\n" ); document.write( "\"d%5E2=50\"\r
\n" ); document.write( "\n" ); document.write( "\"d=sqrt%2850%29\"\r
\n" ); document.write( "\n" ); document.write( "\"d=7.07\"\r
\n" ); document.write( "\n" ); document.write( "then radius is \"r=d%2F2=7.07%2F2=3.535\"\r
\n" ); document.write( "\n" ); document.write( "so, the circumference of the circle is:\r
\n" ); document.write( "\n" ); document.write( "\"circumference=2r%2Api\"\r
\n" ); document.write( "\n" ); document.write( "\"circumference=2%2A3.535%2A3.14\"\r
\n" ); document.write( "\n" ); document.write( "\"circumference=22.1998\"
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