document.write( "Question 736995: the length of this rectangle is 1cm more than it's width. it has an area of 426cm² find the width correct to one decimal place \n" ); document.write( "

Algebra.Com's Answer #450118 by checkley79(3341) $\"\"$ $\"About$

You can put this solution on YOUR website!
AREA=LW
\n" ); document.write( "L=W+1
\n" ); document.write( "426=(W+1)W
\n" ); document.write( "426=W^2+W
\n" ); document.write( "W^2+W-426=0
\n" ); document.write( " $\"W+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"$
\n" ); document.write( "W=(-1+-SQRT(1^2-4*1*-426))/2*1
\n" ); document.write( "W=(-1+-SQRT(1+1704)/2
\n" ); document.write( "W=(-1+-SQRT1705)/2
\n" ); document.write( "W=(-1+-41.29/2
\n" ); document.write( "W=(-1+41.29)/2
\n" ); document.write( "W=40.29/2
\n" ); document.write( "W=20.1 ANS.
\n" ); document.write( "L=20.1+1
\n" ); document.write( "L=21.1 ANS.
\n" ); document.write( "PROOF:
\n" ); document.write( "426=21.1+20.1
\n" ); document.write( "426=425.2 \n" ); document.write( "

\n" );