document.write( "Question 737008: log(base7)x+log(base7)(x-1)=log(base7)12 \n" ); document.write( "
Algebra.Com's Answer #450115 by lwsshak3(11628)\"\" \"About 
You can put this solution on YOUR website!
log(base7)x+log(base7)(x-1)=log(base7)12
\n" ); document.write( "\"log%287%2C%28x%29%29%2Blog%287%2C%28x-1%29%29=log%287%2C%2812%29%29\"
\n" ); document.write( "\"x%28x-1%29=12\"
\n" ); document.write( "\"x%5E2-x-12=0\"
\n" ); document.write( "(x-4)(x+3)=0
\n" ); document.write( "x=-3 (reject, x>0)
\n" ); document.write( "x=4
\n" ); document.write( "
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