document.write( "Question 736993: Completing the Square\r
\n" ); document.write( "\n" ); document.write( "What is half of -4y/3 squared?\r
\n" ); document.write( "\n" ); document.write( "3y^2-4y-1=0\r
\n" ); document.write( "\n" ); document.write( "3y^2/3-4y/3-1/3=0/3\r
\n" ); document.write( "\n" ); document.write( "y^2-4y/3=1/3 This is where I get stuck.\r
\n" ); document.write( "\n" ); document.write( "I'm supposed to take half of -4y/3 and square it. \r
\n" ); document.write( "\n" ); document.write( "I'm not quite understanding how to do it. Do you square both -4 and 3 separately? Then it becomes -16y/9?\r
\n" ); document.write( "\n" ); document.write( "If you halve it, it becomes -2y/1.5?? Should you not have a decimal or a fraction?\r
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Algebra.Com's Answer #450078 by fcabanski(1391)\"\" \"About 
You can put this solution on YOUR website!
Only square half of the coefficient of the y term. Half of -4/3 is -2/3. Square both the numerator and denominator. -2/3 squared is 4/9.


\n" ); document.write( "\"y%5E2-4y%2F3+%2B+4%2F9+=1%2F3+%2B+4%2F9\"


\n" ); document.write( "\"y%5E2-4y%2F3+%2B+4%2F9+=7%2F9\"


\n" ); document.write( "\"%28y-2%2F3%29%5E2+=+7%2F9\"


\n" ); document.write( "y - 2/3 = + or - \"sqrt%287%2F9%29\" = + or - \"sqrt%287%29%2F3%29\"
\n" ); document.write( "y = (2 + or - \"sqrt%287%29\")/3
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Hope the solution helped. Sometimes you need more than a solution. Contact fcabanski@hotmail.com for online, private tutoring, or personalized problem solving (quick for groups of problems.) \n" ); document.write( "

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