document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=736980>Question 736980</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solve for x <BR>\n" );
document.write( "log (7x+33) - log 6 = log (4x-3) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #450070 by </B><A HREF=/tutors/aboutme.mpl?userid=fcabanski><B>fcabanski(1391)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fcabanski><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=450070\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> log a - log b = log (a/b).  <P><BR>\n" );
document.write( "log ((7x+33)/6) = log(4x-3)<P><BR>\n" );
document.write( "raise 10 to the power of both sides of the equation.  That will remove the log (base 10).  10 ^ (log((7x+33)/6) = (7x+33)/6.  10^(log(4x-3)) =  4x-3.   <P><BR>\n" );
document.write( "(7x+33)/6 = 4x-3<P><BR>\n" );
document.write( "7x+33 = 24x-18<P><BR>\n" );
document.write( "51 = 17x<P><BR>\n" );
document.write( "3=x<BR>\n" );
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