document.write( "Question 64360: Can you help me solve this application? I'm trying to solve applications involving parabolas.\r
\n" ); document.write( "\n" ); document.write( "The length of a rectangle is twice the width. The area is 16m^2. Find the length to the nearest hundredth of a meter.\r
\n" ); document.write( "\n" ); document.write( "Thanks
\n" ); document.write( "Liz
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Algebra.Com's Answer #45001 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
The length of a rectangle is twice the width. The area is 16 m^2. Find the length to the nearest hundredth of a meter.
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\n" ); document.write( "Let x = the width
\n" ); document.write( "Then 2x = the length
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\n" ); document.write( "Area:
\n" ); document.write( "x*2x = 16
\n" ); document.write( "2x^2 = 16
\n" ); document.write( "x^2 = 16/2
\n" ); document.write( "x^2 = 8
\n" ); document.write( "x = SqRt(8)
\n" ); document.write( "x = 2.828
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\n" ); document.write( "Length = 2* 2.828 = 5.66 meters
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\n" ); document.write( "Check 2.83*5.66 = 16.02 because of rounding off
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