document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=736771>Question 736771</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How is this questions solved?\r<BR>\n" );
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document.write( "Consider the polynomial function p(x)=2x^3-9x^2+4x+15<BR>\n" );
document.write( "Show using the intermediate therem that p(x) has a zero between -2 and 0. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #449995 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=449995\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> See the web site below for additional explanation:<BR>\n" );
document.write( "http://www.mathsisfun.com/algebra/intermediate-value-theorem.html<BR>\n" );
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document.write( "p(x)=2x^3-9x^2+4x+15<BR>\n" );
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document.write( "p(-2)=2(-2)^3-9(-2)^2+4(-2)+15<BR>\n" );
document.write( "p(-2)=2(4)-9(4)+(-8)+15<BR>\n" );
document.write( "p(-2)=8-36-8+15<BR>\n" );
document.write( "p(-2)=-36+15<BR>\n" );
document.write( "p(-2)=-21  (negative)<BR>\n" );
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document.write( "p(0)=2(0)^3-9(0)^2+4(0)+15<BR>\n" );
document.write( "p(0)=0-0+0+15<BR>\n" );
document.write( "p(0)=15<BR>\n" );
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document.write( "Since p(-2) is NEGATIVE the function MUST cross y=0 to get to p(0).  Because p(0) is POSITIVE.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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