document.write( "Question 736666: Using whole units and the area given, find the dimentions of the rectangle with the shortest perimeter. Area=188. My teacher told me to do a multiplication problem with numbers similar to each other. I've tried 13x13,13x14,14x12,12x15(which might not be close enough together) and 12x17. Nothing has worked. Please help. Thanks! \n" ); document.write( "

Algebra.Com's Answer #449971 by rothauserc(4718) $\"\"$ $\"About$

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we know length (l) * width (w) = Area (A) for a rectangle and\r
\n" ); document.write( "\n" ); document.write( "2*l + 2*w = Perimeter (P)\r
\n" ); document.write( "\n" ); document.write( "we are given l * w = 188 (A)\r
\n" ); document.write( "\n" ); document.write( "let's list the factors as pairs (l, w) when multiplied together give 188\r
\n" ); document.write( "\n" ); document.write( "(188, 1), (94, 2), (47, 4)\r
\n" ); document.write( "\n" ); document.write( "it remains to calculate the pair with the smallest perimeter\r
\n" ); document.write( "\n" ); document.write( "(188, 1) = 2*188 + 2*1 = 378 (P)
\n" ); document.write( "(94, 2) = 2*94 + 2*2 = 192 (P)
\n" ); document.write( "(47, 4) = 2*47 + 2*4 = 102 (P)\r
\n" ); document.write( "\n" ); document.write( "therefore the rectangle with length 47 and width 4 has the shortest Perimeter
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