document.write( "Question 64359: Can you help me solve this application? \r
\n" ); document.write( "\n" ); document.write( "A particle moves along a straight line according to the formula s=2t^2+t-6, where s represents the distance in inches from the beginning point, and t represents the time in seconds. Find the time (to the nearest hundredth of a second when the particle is 5 incesh from the beginning point.\r
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\n" ); document.write( "Elizabeth
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Algebra.Com's Answer #44996 by Edwin McCravy(20060)\"\" \"About 
You can put this solution on YOUR website!
Can you help me solve this application? \r\n" );
document.write( "A particle moves along a straight line \r\n" );
document.write( "according to the formula s=2tイ + t - 6, where \r\n" );
document.write( "s represents the distance in inches from the \r\n" );
document.write( "beginning point, and t represents the time \r\n" );
document.write( "in seconds. Find the time (to the nearest \r\n" );
document.write( "hundredth of a second when the particle is \r\n" );
document.write( "5 inches from the beginning point. \r\n" );
document.write( "Thanks\r\n" );
document.write( "Elizabeth\r\n" );
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document.write( "s = 2tイ + t - 6\r\n" );
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document.write( "Just substitute 5 for s and solve for t:\r\n" );
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document.write( "5 = 2tイ + t - 6\r\n" );
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document.write( "0 = 2tイ + t - 11\r\n" );
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document.write( "That won't factor:\r\n" );
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document.write( "      2tイ + t - 11 = 0\r\n" );
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document.write( "So we use the quadratic formula:\r\n" );
document.write( "                  ______ \r\n" );
document.write( "            -b ア bイ-4ac\r\n" );
document.write( "        x = 覧覧覧覧覧覧予r\n" );
document.write( "                2a \r\n" );
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document.write( "where a = 2; b = 1; c = -11; x = t\r\n" );
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document.write( "                     ______________ \r\n" );
document.write( "             -(1) ア (1)イ-4(2)(-11)\r\n" );
document.write( "        t = 覧覧覧覧覧覧覧覧覧覧覧覧\r\n" );
document.write( "                     2(2) \r\n" );
document.write( "                   _____ \r\n" );
document.write( "             -1 ア 1+88\r\n" );
document.write( "        t = 覧覧覧覧覧覧予r\n" );
document.write( "                 4\r\n" );
document.write( "\r\n" );
document.write( "                   __ \r\n" );
document.write( "             -1 ア 89\r\n" );
document.write( "        t = 覧覧覧覧覧\r\n" );
document.write( "                 4\r\n" );
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document.write( "                      \r\n" );
document.write( "Using the +, we get t about 2.108495283 seconds, \r\n" );
document.write( "or about 2.11 seconds, to the nearest hundredth\r\n" );
document.write( "of a second.\r\n" );
document.write( "                      \r\n" );
document.write( "Using the -, we get a negative value, which we discard.\r\n" );
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document.write( "Edwin
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