document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=64368>Question 64368</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/093979862x/algebrahomeworkh>An Incremental Development</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> help to simplify\r<BR>\n" );
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document.write( "-2^2 - (-2)^2 - absolute vale of 2^2 - 3^2 end absolute value - 1/-2^3 - 3^0(-2^3 - 3^2)\r<BR>\n" );
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document.write( "thank u </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #44995 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=44995\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> -2^2 - (-2)^2 - absolute vale of 2^2 - 3^2 <BR>\n" );
document.write( "= -4 - 4 - 4 - 9<BR>\n" );
document.write( "=-21<BR>\n" );
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document.write( "absolute value - 1/-2^3 - 3^0(-2^3 - 3^2) <BR>\n" );
document.write( "= (1/8) - 1(-8 - 9)<BR>\n" );
document.write( "= (1/8) -(-17)<BR>\n" );
document.write( "=  17 1/8<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( " </SPAN>\n" );
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