document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=736573>Question 736573</A>: <I><SPAN STYLE=\"word-break: break-all;\"> \r<BR>\n" );
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document.write( "let x be equal to a number another number is five less than twice x when the two numbers are multiplied the answer is 7 find two possible values for the number<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #449928 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley79><B>checkley79(3341)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley79><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=449928\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> LET X BE THE FIRST NUMBER<BR>\n" );
document.write( "LET 2X-5 BE THE SECOND NUMBER.<BR>\n" );
document.write( "X(2X-5)=7<BR>\n" );
document.write( "2X^2-5X-7=0<BR>\n" );
document.write( "(2X-7)(X+1)=0<BR>\n" );
document.write( "2X-7=0<BR>\n" );
document.write( "2X=7<BR>\n" );
document.write( "X=7/2<BR>\n" );
document.write( "X=3.5 ANS.<BR>\n" );
document.write( "2*X-5=2*3.5-5=7-5=2 ANS.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "3.5*2=7<BR>\n" );
document.write( "7=7 </SPAN>\n" );
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