document.write( "Question 64370: could you help me sketch the graph of the solution to: x^2+y^2or=x-1. Also if you don't mind, please do the same with x>or=|y|, y>or=|-3|, 2y-x\n" ); document.write( "
Algebra.Com's Answer #44992 by stanbon(75887)\"\" \"About 
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could you help me sketch the graph of the solution to: x^2+y^2or=x-1?
\n" ); document.write( "x^2+y^2=9 is a circle with center at (0.0) and a radius of 3.
\n" ); document.write( "x^2+y^2<9 is the interior of the circle.
\n" ); document.write( "y-2x=x-1 is the line y=-x-1 which passes through (0,-1) and (2,-3)
\n" ); document.write( "y-2x>x-1 the the half-plane above the line y=-x-1.
\n" ); document.write( "I can't graph the circle on this site but the line looks like this:
\n" ); document.write( "\"graph%28300%2C200%2C-10%2C10%2C-10%2C10%2C-x-1%29\"
\n" ); document.write( "In the first problem I came up with a line passing through (0,-1) and (1,0)with shading above that line.
\n" ); document.write( "You are correct.
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\n" ); document.write( " Also if you don't mind, please do the same with x>or=|y|, y>or=|-3|, 2y-x\n" ); document.write( "In the second one I came up with a line through (-3), a line through (0,0) and (2,-2); and a v opening right from (0,0)going through (2,2)(2,-2).
\n" ); document.write( "That is the equality graph. The greater than part is the inside of the
\n" ); document.write( "V-shape.
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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