document.write( "Question 736420: A BOAT TRAVELED 336 MILES DOWNSTREAM AND BACK. THE TRIP DOWNSTREAM TOOK 12HOURS. THE TRIP BACK TOOK 14 HOURS. WHAT IS THE SPEED OF THE BOAT IN STILL WATER? WHAT IS THE SPEED OF THE CURRENT? SOLVE USING A SYSTEM OF TWO EQUATIONS \n" ); document.write( "
Algebra.Com's Answer #449832 by mananth(16946)\"\" \"About 
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Boat speed speed =x mph
\n" ); document.write( "current speed =y mph
\n" ); document.write( "against current 14 hours
\n" ); document.write( "with current 12 hours
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\n" ); document.write( "Distance against 336 miles distance with 336 miles
\n" ); document.write( "t=d/r against current -
\n" ); document.write( "336 / ( x - y )= 14
\n" ); document.write( "14 ( x - y ) = 336
\n" ); document.write( "14 x - 14 y = 336 ....................1
\n" ); document.write( "
\n" ); document.write( "336 / ( x + y )= 12
\n" ); document.write( "12 ( x + y ) = 336
\n" ); document.write( "12 x + 12 y = 336 ...............2
\n" ); document.write( "Multiply (1) by 6
\n" ); document.write( "Multiply (2) by 7
\n" ); document.write( "we get
\n" ); document.write( "84 x + -84 y = 2016
\n" ); document.write( "84 x + 84 y = 2352
\n" ); document.write( "168 x = 4368
\n" ); document.write( "/ 168
\n" ); document.write( "x = 26.00 mph
\n" ); document.write( "
\n" ); document.write( "plug value of x in (1) y
\n" ); document.write( "14 x -14 y = 336
\n" ); document.write( "364 -14 -364 = 336
\n" ); document.write( "-14 y = 336
\n" ); document.write( "-14 y = -28 mph
\n" ); document.write( " y = 2.00
\n" ); document.write( "Boat speed speed 26.00 mph
\n" ); document.write( "current speed 2.00 mph
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\n" ); document.write( "m.ananth@hotmail.ca
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