document.write( "Question 736297: Lily's family took a motor boat 24 km down a river for a picnic. It took them 1 hr to get to the picnic spot. The ride back to the dock took an hour and a half. What was the average speed at which the river flowed? What would the boat's average speed be on a lake? \n" ); document.write( "
Algebra.Com's Answer #449772 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Boat speed =x kph \n" ); document.write( "current speed =y kph \n" ); document.write( "against current 1.5 hours \n" ); document.write( "with current 1 hours \n" ); document.write( " \n" ); document.write( "Distance against 24 miles distance with 24 miles \n" ); document.write( "t=d/r against current - \n" ); document.write( "24.00 / ( x - y )= 1.50 \n" ); document.write( "1.50 ( x - y ) = 24.00 \n" ); document.write( "1.50 x - 1.50 y = 24.00 ....................1 \n" ); document.write( " \n" ); document.write( "24.00 / ( x + y )= 1.00 \n" ); document.write( "1.00 ( x + y ) = 24.00 \n" ); document.write( "1.00 x + 1.00 y = 24.00 ...............2 \n" ); document.write( "Multiply (1) by 1.00 \n" ); document.write( "Multiply (2) by 1.50 \n" ); document.write( "we get \n" ); document.write( "1.50 x + -1.50 y = 24.00 \n" ); document.write( "1.50 x + 1.50 y = 36.00 \n" ); document.write( "3.00 x = 60.00 \n" ); document.write( "/ 3.00 \n" ); document.write( "x = 20.00 mph \n" ); document.write( " \n" ); document.write( "plug value of x in (1) y \n" ); document.write( "1.50 x -1.50 y = 24.00 \n" ); document.write( "30.00 -1.50 -30.00 = 24.00 \n" ); document.write( "-1.50 y = 24.00 \n" ); document.write( "-1.50 y = -6.00 kph \n" ); document.write( " y = 4.00 \n" ); document.write( "Boat speed 20.00 mph \n" ); document.write( "current speed 4.00 kph \n" ); document.write( " \n" ); document.write( " |