document.write( "Question 736258: sin2x=cosx \n" ); document.write( "

Algebra.Com's Answer #449744 by Alan3354(69443) $\"\"$ $\"About$

You can put this solution on YOUR website!
sin2x=cosx
\n" ); document.write( " $\"sin%282x%29+=+cos%28x%29\"$
\n" ); document.write( " $\"2sin%28x%29%2Acos%28x%29+=+cos%28x%29\"$
\n" ); document.write( " $\"2sin%28x%29cos%28x%29+-++cos%28x%29=+0\"$
\n" ); document.write( " $\"2sin%28x%29cos%28x%29+-++cos%28x%29=+0\"$
\n" ); document.write( " $\"cos%28x%29%2A%282sin%28x%29+-+1%29+=+0\"$
\n" ); document.write( "cos(x) = 0
\n" ); document.write( "----------------
\n" ); document.write( "2sin(x) - 1 = 0
\n" ); document.write( "sin(x) = 1/2
\n" ); document.write( "You can finish and check.
\n" ); document.write( " \n" ); document.write( "

\n" );