document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=736211>Question 736211</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Using the sum/difference formula find: sin(pi/12)\r<BR>\n" );
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document.write( "In class, we started by using the unit circle and searching for radicals that can be added to have the same denominator as the fraction given.  My only issue is that how can I get the numerator to equal ONE pi.   </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #449738 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=449738\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Using the sum/difference formula find: sin(pi/12) <BR>\n" );
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document.write( "sin(pi/12) = sin[(pi/3)-(pi/4)] = sin(pi/3)cos(pi/4)-cos(pi/3)sin(pi/4)<BR>\n" );
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document.write( "= (sqrt(3)/2)(sqrt(2)/2) - (1/2)(sqrt(2)/2)<BR>\n" );
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document.write( "= [sqrt(6)/4] - sqrt(2)/4)<BR>\n" );
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document.write( "= (sqrt(6)-sqrt(2))/4<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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