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document.write( "A rectangle is 4 feet longer than it is wide. It's perimeter is 60 feet. Find the length an width of the rectangle \n" );
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Algebra.Com's Answer #449706 by checkley79(3341)![]() ![]() ![]() You can put this solution on YOUR website! L=W+4 \n" ); document.write( "P=2L+2W \n" ); document.write( "60=2(W+4)+2W \n" ); document.write( "60=2W+8+2W \n" ); document.write( "60-8=4W \n" ); document.write( "52=4W \n" ); document.write( "W=52/4 \n" ); document.write( "W=13 ANS. FOR THE WIDTH. \n" ); document.write( "L=13+4=17 ANS. FOR THE LENGTH. \n" ); document.write( "PROOF: \n" ); document.write( "60=2*17+2*13 \n" ); document.write( "60=34+26 \n" ); document.write( "60=60 \n" ); document.write( " |