document.write( "Question 736093: \r
\n" ); document.write( "\n" ); document.write( "A rectangle is 4 feet longer than it is wide. It's perimeter is 60 feet. Find the length an width of the rectangle
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Algebra.Com's Answer #449706 by checkley79(3341)\"\" \"About 
You can put this solution on YOUR website!
L=W+4
\n" ); document.write( "P=2L+2W
\n" ); document.write( "60=2(W+4)+2W
\n" ); document.write( "60=2W+8+2W
\n" ); document.write( "60-8=4W
\n" ); document.write( "52=4W
\n" ); document.write( "W=52/4
\n" ); document.write( "W=13 ANS. FOR THE WIDTH.
\n" ); document.write( "L=13+4=17 ANS. FOR THE LENGTH.
\n" ); document.write( "PROOF:
\n" ); document.write( "60=2*17+2*13
\n" ); document.write( "60=34+26
\n" ); document.write( "60=60
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