document.write( "Question 64329: please help!\r
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document.write( "1. Determine all x-intercepts of the rational function f(x)=x^2-2x/(x+4)^2\r
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document.write( "2. Find the x-coordinates of the points of intersection between the two functions x^2+y^2=113 and x+y=-15\r
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document.write( "3. Give the equation of a line that passes through the point(7,4) and is perpendicular to the line whose equation is given by 4x+5y=8\r
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document.write( "Thank you! \n" );
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Algebra.Com's Answer #44969 by venugopalramana(3286)![]() ![]() You can put this solution on YOUR website! please help! \n" ); document.write( "1. Determine all x-intercepts of the rational function f(x)=x^2-2x/(x+4)^2 \n" ); document.write( "X^2 - 2X/(X+4)^2 = Y = 0 \n" ); document.write( "X[X-{2/(X+4)^2}]=0 \n" ); document.write( "X=0....IS THE X INTERCEPT \n" ); document.write( "THE OTHER POSSIBILITY IS \n" ); document.write( "X=2/(X+4)^2 \n" ); document.write( "HAS NO SOLUION SINCE X HAS TO BE POSITIVE AND AT X =0 THE MINIMUM VALUE WE GET LHS =0 ...RHS = 0.125...AS X INCREASES LHS INCREASES AND RHS DECREASES. \n" ); document.write( "X=0 IS THE ONLY X INTERCEPT \n" ); document.write( "2. Find the x-coordinates of the points of intersection between the two functions x^2+y^2=113 and x+y=-15 \n" ); document.write( "(X+Y)^2= (-15)^2=225 \n" ); document.write( "X^+Y^2 = 113.................2 \n" ); document.write( "2XY = 225-213=12...................3 \n" ); document.write( "(X-Y)^2=113-12=101...................4 \n" ); document.write( "X-Y=SQRT(101)=10.05............5 \n" ); document.write( "X+Y=-15................1, \n" ); document.write( "EQN.1+EQN.5 GIVES \n" ); document.write( "2X=-4.95 \n" ); document.write( " X=-2.475 \n" ); document.write( "3. Give the equation of a line that passes through the point(7,4) and is perpendicular to the line whose equation is given by 4x+5y=8 \n" ); document.write( "PERPENDICULAR LINE HAS EQN. OF TYPE \n" ); document.write( "5X-4Y=K......IT PASSES THROUGH (7,4) \n" ); document.write( "5*7-4*4=K \n" ); document.write( "19=K \n" ); document.write( "EQN. OF PERPENDICULAR IS 5X-4Y=19\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Thank you! \n" ); document.write( " \n" ); document.write( " |