document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=736047>Question 736047</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do I find tan(sin^-1 1/3) by using the unit circle? I know you have to find the sin of 1/3 by looking in quadrant 1 or 4. and X is the cos and Y is the sin but I can't find 1/3 on my unit circle... I also know that Tan is sin over cos but do you divide the sin and the cos to get tan? I have no idea what I'm doing. Please explain it to me? Thank you  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #449644 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=449644\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How do I find tan(sin^-1 1/3) by using the unit circle?<BR>\n" );
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document.write( "You have a certain angle.<BR>\n" );
document.write( "Its sin = y/r = 1/3.<BR>\n" );
document.write( "So y = 1 and r = 3<BR>\n" );
document.write( "-----<BR>\n" );
document.write( "The tan is y/x so you have to find \"x\":<BR>\n" );
document.write( "x = sqrt[r^2-y^2] = sqrt[9-1] = 2sqrt(2)<BR>\n" );
document.write( "-----<BR>\n" );
document.write( "Therefore tan(your angle) = y/x = 1/sqrt(8) = (1/8)sqrt(8)<BR>\n" );
document.write( "-----<BR>\n" );
document.write( "Note: You don't have to know the angle.<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.  </SPAN>\n" );
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