document.write( "Question 736018: I am a librarian. A patron needs a solution to this problem:\r
\n" ); document.write( "\n" ); document.write( "The speed of a boat in still waters is 10 km/h
\n" ); document.write( "The boat travels 12 km upstream and 28 km downstream in a total of 4 hours.
\n" ); document.write( "What is the speed of the stream?\r
\n" ); document.write( "\n" ); document.write( "Thanks
\n" ); document.write( "

Algebra.Com's Answer #449635 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
let speed of current be c kph\r
\n" ); document.write( "\n" ); document.write( "upstream speed = 10-c
\n" ); document.write( "upstream distance = 12 \r
\n" ); document.write( "\n" ); document.write( "down stream speed = 10+c
\n" ); document.write( "down stream distance = 28 km\r
\n" ); document.write( "\n" ); document.write( "upstream time + downstream time = 4\r
\n" ); document.write( "\n" ); document.write( "t=d/r\r
\n" ); document.write( "\n" ); document.write( "12/(10-c) + 28/(10+c)= 4\r
\n" ); document.write( "\n" ); document.write( "multiply the equation by (10+c)(10-c)\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "12(10+c)+28(10-c)=4(10+c)(10-c)\r
\n" ); document.write( "\n" ); document.write( "120+12c+280-28c=4(100-c^2)\r
\n" ); document.write( "\n" ); document.write( "400-16c=400-4c^2\r
\n" ); document.write( "\n" ); document.write( "re arrange
\n" ); document.write( "4c^2=16c\r
\n" ); document.write( "\n" ); document.write( "/4c
\n" ); document.write( "c=4\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "current speed = 4 kph
\n" ); document.write( "
\n" );