document.write( "Question 735931: Randy is four times as old as Marie. In 12yr, Marie's age will be half of Randy's age. How old are they now? \n" ); document.write( "
Algebra.Com's Answer #449615 by ptaylor(2198)\"\" \"About 
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Let x=Marie's age; x+12=Marie's age in 12 years
\n" ); document.write( "Then 4x=Randy's age; 4x+12=Randy's age in 12 years\r
\n" ); document.write( "\n" ); document.write( "Now we are told that:
\n" ); document.write( "x+12=1/2(4x+12) simplify
\n" ); document.write( "x+12=2x+6 subtract x and also 6 from each side
\n" ); document.write( "x-x+12-6=2x-x+6-6
\n" ); document.write( "6=x or
\n" ); document.write( "x=6 years old-------------Marie's age now
\n" ); document.write( "4x=4*6=24 years old--------Randy's age now\r
\n" ); document.write( "\n" ); document.write( "CK
\n" ); document.write( "6+12=1/2(24+12)
\n" ); document.write( "18=1/2(36)
\n" ); document.write( "18=18
\n" ); document.write( "Hope this helps--ptaylor
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