document.write( "Question 735931: Randy is four times as old as Marie. In 12yr, Marie's age will be half of Randy's age. How old are they now? \n" ); document.write( "
Algebra.Com's Answer #449615 by ptaylor(2198)![]() ![]() You can put this solution on YOUR website! Let x=Marie's age; x+12=Marie's age in 12 years \n" ); document.write( "Then 4x=Randy's age; 4x+12=Randy's age in 12 years\r \n" ); document.write( "\n" ); document.write( "Now we are told that: \n" ); document.write( "x+12=1/2(4x+12) simplify \n" ); document.write( "x+12=2x+6 subtract x and also 6 from each side \n" ); document.write( "x-x+12-6=2x-x+6-6 \n" ); document.write( "6=x or \n" ); document.write( "x=6 years old-------------Marie's age now \n" ); document.write( "4x=4*6=24 years old--------Randy's age now\r \n" ); document.write( "\n" ); document.write( "CK \n" ); document.write( "6+12=1/2(24+12) \n" ); document.write( "18=1/2(36) \n" ); document.write( "18=18 \n" ); document.write( "Hope this helps--ptaylor \n" ); document.write( " |