document.write( "Question 735809: Log5x-Log(2x-1)=Log7 \n" ); document.write( "
Algebra.Com's Answer #449612 by lwsshak3(11628)\"\" \"About 
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Log5x-Log(2x-1)=Log7
\n" ); document.write( "log[5x/(2x-1)]=log(7)
\n" ); document.write( "5x/(2x-1)=7
\n" ); document.write( "5x=14x-7
\n" ); document.write( "9x=7
\n" ); document.write( "x=7/9
\n" ); document.write( "
\n" );