document.write( "Question 64225This question is from textbook Intermediate Algebra through applications
\n" ); document.write( ": I'm stumped about this problem. A rocket is fired into the air. The height of the rocket h(t) after t seconds is given by the formula h(t)=80t-16^2. After how many seconds is the rocket 96 feet high
\n" ); document.write( "This is what I started:
\n" ); document.write( "h(t)=80-16^2
\n" ); document.write( "h(96)=80(96)-16(96)^2 Now I am lost???? Can you show me how to complete this problem? Thank you so Much!
\n" ); document.write( "

Algebra.Com's Answer #44958 by 303795(602)\"\" \"About 
You can put this solution on YOUR website!
You have not written down the formula correctly
\n" ); document.write( "It is not (h(t)=80-16^2) but rather(h(t)=80t-16t^2)
\n" ); document.write( "You have also confused the time which is t with the height which is h(t) because the height varies with time. \r
\n" ); document.write( "\n" ); document.write( "You have to find the time (t)
\n" ); document.write( "h(t) means the height at that time t. You are told that it is 96.
\n" ); document.write( "so \"h%28t%29=80t-16t%5E2\"
\n" ); document.write( "\"96=80t-16t%5E2\"
\n" ); document.write( "\"0=80t-16t%5E2-96\"
\n" ); document.write( "\"0=-16t%5E2%2B80t-96\"
\n" ); document.write( "Multiply both sides by -1
\n" ); document.write( "\"0=16t%5E2-80t%2B96\"
\n" ); document.write( "Divide both sides by 16
\n" ); document.write( "\"0=t%5E2-5t%2B6\"
\n" ); document.write( "Factorise
\n" ); document.write( "\"0=%28t-2%29%28t-3%29\"
\n" ); document.write( "so t=2 or t=3
\n" ); document.write( "So the rocket is at 96 feet after 2 seconds and again at 96 feet after 3 seconds as it comes back down again.
\n" ); document.write( "
\n" ); document.write( "
\n" );