document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=735749>Question 735749</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how do you find sin600 using the double angle identity.the farthest I had gotten was sin(2*600)=2sin(600)cos(600). Cos 600 being -1/2 and sin 600 being <BR>\n" );
document.write( "2*radical 3/2. Any help would be greatly appreciated :) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #449540 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=449540\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> how do you find sin600 using the double angle identity.the farthest I had gotten was sin(2*600)=2sin(600)cos(600). Cos 600 being -1/2 and sin 600 being <BR>\n" );
document.write( "2*radical 3/2. Any help would be greatly appreciated :)<BR>\n" );
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document.write( "sin(600) = 2sin(300)cos(300) **** not sin(600).... <BR>\n" );
document.write( "= 2*(-sqrt(3)/2)*(1/2)<BR>\n" );
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