document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=735737>Question 735737</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do find the factor of x^2-x-20? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #449532 by </B><A HREF=/tutors/aboutme.mpl?userid=blwinbbbles><B>blwinbbbles(106)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=blwinbbbles><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=blwinbbbles><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=449532\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> you find the factor by starting with factors of 20..\r<BR>\n" );
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document.write( "so you can have 1x20, 2x10, 4x5,  of these pairs would be most likely to produce a -x...my guess would be 4 and 5...since it is a -20 in the equation then there need to be one neg number and one positive number.\r<BR>\n" );
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document.write( "so I would start with:\r<BR>\n" );
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document.write( "(x-5)(x+4) this will equal\r<BR>\n" );
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document.write( "x^2 + 4x - 5x - 20 combine like terms\r<BR>\n" );
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document.write( "x^2 - x - 20\r<BR>\n" );
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document.write( "so the factors are:\r<BR>\n" );
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document.write( "(x-5) and (x + 4)<BR>\n" );
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