document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=735595>Question 735595</A>: <I><SPAN STYLE=\"word-break: break-all;\"> \r<BR>\n" );
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document.write( "A pharmacist has a 30% and 80% iodine solutions on hand.  How many liters of each iodine dilution will be required to produce 8 liters of a 50% iodine mixture? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #449515 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley79><B>checkley79(3341)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley79><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=449515\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .80X+.30(8-X)=.50*8<BR>\n" );
document.write( ".80X+.24-.30X=4<BR>\n" );
document.write( ".50X=40-.24<BR>\n" );
document.write( ".50X=.16<BR>\n" );
document.write( "X=.16/.5<BR>\n" );
document.write( "X=3.2 LITERS ANS. FOR THE 80% SOLUTION IS USED.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( ".80*3.2+.30(8-3.2)=.50*8<BR>\n" );
document.write( "2.56+.30*4.8=4<BR>\n" );
document.write( "2.56+1.44=4<BR>\n" );
document.write( "4=4 </SPAN>\n" );
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