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document.write( "A tugboat goes 180 miles upstream in 10 hours. The return trip downstream takes 5 hours. Find the speed of the tugboat without a current and the speed of the current. \n" );
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Algebra.Com's Answer #449508 by checkley79(3341)![]() ![]() ![]() You can put this solution on YOUR website! D=RT \n" ); document.write( "180=(R-C)10 \n" ); document.write( "180=10R-10C DIVIDE BY 2 & ADD. \n" ); document.write( "180=(R+C)5 \n" ); document.write( "180=5R+5C \n" ); document.write( "90=5R-5C \n" ); document.write( "--------------- \n" ); document.write( "270=10R \n" ); document.write( "R=270/10 \n" ); document.write( "R=27 MPH. ANS. FOR THE RATE OF THE BOAT. \n" ); document.write( "180=(27-C)10 \n" ); document.write( "180=270-10C \n" ); document.write( "10C=270-180 \n" ); document.write( "10C=90 \n" ); document.write( "C=90/10 \n" ); document.write( "C=9 MPH. ANS.FOR THE CURRENT. \n" ); document.write( "PROOF: \n" ); document.write( "180(27+9)5 \n" ); document.write( "180=36*5 \n" ); document.write( "180=180 \n" ); document.write( " |