document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=8070>Question 8070</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hello i have a question\r<BR>\n" );
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document.write( "A bicyclist rode into the country for 5/h in returning her speed was 5 mi/h faster and the trip took 4/h. What was her speed each way?\r<BR>\n" );
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document.write( "Thank you so much for your help a mom </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #4495 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=4495\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You can use the distance formula: d = rt  (distance = rate X time)\r<BR>\n" );
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document.write( "For the outbound trip:<BR>\n" );
document.write( " d1 = (r1)(t1)<BR>\n" );
document.write( "d1 = (r1)(5 hrs)\r<BR>\n" );
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document.write( "For the return trip:\r<BR>\n" );
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document.write( "d2 = (r2)(t2)<BR>\n" );
document.write( "d2 = (r2)(4 hrs)\r<BR>\n" );
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document.write( "But, d1 = d2 (Same distance outbound as return)<BR>\n" );
document.write( "And, r2 = r1+5 (Return speed was 5 mph more than the outbound speed)\r<BR>\n" );
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document.write( "So we can write: d1 = d2 or;\r<BR>\n" );
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document.write( "(r1)(5) = (r1+5)(4)  Simplify and solve for r1.<BR>\n" );
document.write( "5(r1) = 4(r1) + 20<BR>\n" );
document.write( "r1 = 20 mph  Outbound speed.<BR>\n" );
document.write( "r2 = r1+5 mph = (20+5) mph = 25 mph Return speed. </SPAN>\n" );
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