document.write( "Question 735645: Sketch the graph of a parabola and give the vertex, focal point, and directrix.\r
\n" ); document.write( "\n" ); document.write( "A) x^2-6x-3y+3=0\r
\n" ); document.write( "\n" ); document.write( "B) 3x^2-12x+2y-10=0
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Algebra.Com's Answer #449497 by lynnlo(4176)\"\" \"About 
You can put this solution on YOUR website!
(A)X^2-6X-3Y+3=0
\n" ); document.write( "(3,-2)=======(3,-5/4)===========Y=-11
\n" ); document.write( "VERTEX=======FOCI==============DIRECTRIX
\n" ); document.write( "(B)3X^2-12X+2Y-10=0
\n" ); document.write( "(2,11)=======(2,65/6)==========Y=67/6
\n" ); document.write( "VERTEX======FOCI==============DIRECTRIX
\n" ); document.write( "IN CASE YOU DON'T KNOW HOW TO GRAPH YOUR PROBLEM
\n" ); document.write( "SEND ME AN E-MAIL AND I WILL SEND THE GRAPH TO YOU
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