document.write( "Question 735590: did I do this right if not can you tell me what I did wrong\r
\n" ); document.write( "\n" ); document.write( "2x + y = 5
\n" ); document.write( "x − 2y = 10\r
\n" ); document.write( "\n" ); document.write( "y = 5 − 2x
\n" ); document.write( "x − 2(5 − 2x) = 10
\n" ); document.write( "x − 10 + 4x = 10
\n" ); document.write( "5x − 10 = 10
\n" ); document.write( "5x = 0
\n" ); document.write( "x = 0\r
\n" ); document.write( "\n" ); document.write( "2(0) + y = 5
\n" ); document.write( "y = 5
\n" ); document.write( "

Algebra.Com's Answer #449471 by rothauserc(4718)\"\" \"About 
You can put this solution on YOUR website!
The next step after 5x-10=10 should be\r
\n" ); document.write( "\n" ); document.write( "5x=20 (add 10 to both sides of =)\r
\n" ); document.write( "\n" ); document.write( "and x=4\r
\n" ); document.write( "\n" ); document.write( "then (2*4) + y = 5 and y = -3
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