document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=735379>Question 735379</A>: <I><SPAN STYLE=\"word-break: break-all;\"> IM having trouble with this quadratic equation a2+6a+3=0.will you please help me solve it? Thank you. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #449417 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=449417\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> We are given  a^2+6a+3=0\r<BR>\n" );
document.write( "\n" );
document.write( "We need to use the quadratic formula \r<BR>\n" );
document.write( "\n" );
document.write( "x= (-b plus or minus sqrt(b^2-4ac)) / 2a\r<BR>\n" );
document.write( "\n" );
document.write( "substituting\r<BR>\n" );
document.write( "\n" );
document.write( "x = (-6 + sqrt(36-4*3))/2 = -.55<BR>\n" );
document.write( "x = (-6 - sqrt(36-4*3))/2 = -5.45<BR>\n" );
document.write( "  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );