document.write( "Question 64259This question is from textbook Algebra 1
\n" ); document.write( ": A ship travels from New York to Southampton,England at 33 mph. A plane traveling 605 mph takes 104 hours less to make the same trip. How far apart are the two cities? \n" ); document.write( "
Algebra.Com's Answer #44940 by ptaylor(2198)\"\" \"About 
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We'll let x=amount of time it takes the ship travelliing at 33mph
\n" ); document.write( "then x-104=amount of time it takes the plane travelling at 605mph\r
\n" ); document.write( "\n" ); document.write( "we'll use the formula: Distance (d)=(rate(r))(time(t)) or d=rt\r
\n" ); document.write( "\n" ); document.write( "we know that both the ship and the plane travel the same distance which is the distance between the two cities:\r
\n" ); document.write( "\n" ); document.write( "rt(ship)=rt(plane)
\n" ); document.write( "rt of ship is 33x and
\n" ); document.write( "rt of plane is 605(x-104) so our equation to solve is:\r
\n" ); document.write( "\n" ); document.write( "33x=605(x-104)
\n" ); document.write( "33x=605x-62,920 simplifying we get:
\n" ); document.write( "-572x=-62,920
\n" ); document.write( "x=110 hours is the time it takes the ship
\n" ); document.write( "x-104=110=104=6 hours is the time it takes the plane\r
\n" ); document.write( "\n" ); document.write( "rt (ship)=distance between the two cities = 33(110)=3630 miles
\n" ); document.write( "or
\n" ); document.write( "rt (plane)=distance between the two cities = 605(6)=3630 miles\r
\n" ); document.write( "\n" ); document.write( "Hope this helps. Happy holidays.----ptaylor\r
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