document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=735331>Question 735331</A>: <I><SPAN STYLE=\"word-break: break-all;\"> So my equation is 2/3x-22=14 I am doing what it tells me to do what ever it equals is what x = so that means it is 14 so I filled it in 22-2/3+14 solve </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #449394 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=449394\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2/3x-22=14<BR>\n" );
document.write( "Assuming you mean (2/3)x-22=14 and not 2/(3x) - 22=14:<BR>\n" );
document.write( "2/3x-22=14<BR>\n" );
document.write( "Multiply thru by 3<BR>\n" );
document.write( "2x - 66 = 42<BR>\n" );
document.write( "Add 66<BR>\n" );
document.write( "2x = 108<BR>\n" );
document.write( "x = 54<BR>\n" );
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document.write( "Less talk and more effort might be a good idea. </SPAN>\n" );
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