document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=735270>Question 735270</A>: <I><SPAN STYLE=\"word-break: break-all;\"> sqrt6 sin2t- sqrt3 tan2t=0\r<BR>\n" );
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document.write( "I know I can make tan 2t into sin2t/cos2t so I am using like-terms but I am not sure what to do with the square roots or how to even begin to solve this.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #449354 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=449354\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> sqrt6 sin2t- sqrt3 tan2t=0<BR>\n" );
document.write( "sqrt6 sin2t- sqrt3 sin2t/cos2t=0<BR>\n" );
document.write( "sin2t*(sqrt(6) - sqrt(3)/cos2t) = 0<BR>\n" );
document.write( "sin2t = 0<BR>\n" );
document.write( "t = 0<BR>\n" );
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document.write( "(sqrt(6) - sqrt(3)/cos2t) = 0<BR>\n" );
document.write( "sqrt(6) - sqrt(3) = 0<BR>\n" );
document.write( "Inconsistent, no solution.<BR>\n" );
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