document.write( "Question 735166: IF A= $2400, P= $2100, t=3, solve A=P(1+r)^t for r. \n" ); document.write( "
Algebra.Com's Answer #449344 by nerdybill(7384)\"\" \"About 
You can put this solution on YOUR website!
IF A= $2400, P= $2100, t=3, solve A=P(1+r)^t for r.
\n" ); document.write( ".
\n" ); document.write( "A=P(1+r)^t
\n" ); document.write( "plug in given values:
\n" ); document.write( "2400 = 2100(1+r)^3
\n" ); document.write( "2400/2100 = (1+r)^3
\n" ); document.write( "8/7 = (1+r)^3
\n" ); document.write( "(8/7)^(1/3) = 1+r
\n" ); document.write( "1.0455 - 1 = r
\n" ); document.write( "0.0455 = r
\n" ); document.write( "or
\n" ); document.write( "4.6% = r\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );