document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=735204>Question 735204</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please show how to solve:\r<BR>\n" );
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document.write( "Log base10(n^2 – 90n) = 3\r<BR>\n" );
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document.write( "Thank you </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #449324 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=449324\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> we have the following\r<BR>\n" );
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document.write( "log base 10 (n^2 - 90n) = 3\r<BR>\n" );
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document.write( "first take log base 10 of both sides of equal sign and we have,\r<BR>\n" );
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document.write( "n^2 - 90n = log base 10 (3) = .48\r<BR>\n" );
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document.write( "use quadratic formula and we get (note that b is --90 or 90)\r<BR>\n" );
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document.write( "n=(90+square root (90^2-4*1*-.48)) / 2 = 90<BR>\n" );
document.write( "=(90-square root (90^2-4*1*-.48)) / 2 = 0\r<BR>\n" );
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