document.write( "Question 64303: The profit on a watch is given by P = x^2 – 13x – 80, where x is the number of watches sold per day. How many watches were sold on a day when there was a $50 loss? (Hint: \"$50 loss\" means a \"negative $50 profit\". Plug in -50 for P and solve for x) \n" ); document.write( "
Algebra.Com's Answer #44931 by chitra(359)\"\" \"About 
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The expression for profit is given by:\r
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\n" ); document.write( "\n" ); document.write( "P = x^2 – 13x – 80 where x represents the number of watches.\r
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\n" ); document.write( "\n" ); document.write( "By data, it is told that on a particular day there was a loss of $50. That is a negative profit. \r
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\n" ); document.write( "\n" ); document.write( "That is P = - $ 50 \r
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\n" ); document.write( "\n" ); document.write( "Substituting for P in the above equation, we get: \r
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\n" ); document.write( "\n" ); document.write( "\"-50+=+x%5E2+-+13x+-+80\"\r
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\n" ); document.write( "\n" ); document.write( "Adding 50 on both sides of the above equation, we get: \r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2+-+13x+-+80+%2B+50+=+0\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2+-+13x+-+30+=+0\" \r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2+-+10x+-+3x+-+30+=+0\" \r
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\n" ); document.write( "\n" ); document.write( "Taking the first two terms and then grouping them again, we get: \r
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\n" ); document.write( "\n" ); document.write( "\"x%28x+-+10%29+-+3%28x+-+10%29+=+0\"\r
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\n" ); document.write( "\n" ); document.write( "Taking common factors again, we get: \r
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\n" ); document.write( "\n" ); document.write( "(x - 3)(x - 10) = 0 \r
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\n" ); document.write( "\n" ); document.write( "So, (x - 3) = 0 OR (x - 10) = 0 \r
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\n" ); document.write( "\n" ); document.write( "Therefore, x = 3 OR x = 10 \r
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\n" ); document.write( "\n" ); document.write( "Therefore, x = 3 or x = 10 \r
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\n" ); document.write( "\n" ); document.write( "Hence, the solution. \r
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